Question

find the nature of the roots and also find the root of quadratic equation if it exist real

x2+4x-5=0

Answer 1

Answer:

x = 1, -5

Step-by-step explanation:

-$x^2 + 4x - 5\\= x^2 + 5x - x -5\\=x (x+5) - (x+5)\\=(x-1)(x+5)$

Hence the roots are 1 and -5