find the nature of the roots of 2x^2+3x+1=0
Answers
Answered by
1
Step-by-step explanation:
Nature of roots is given by calculating the discriminant
D=b²-4ac
2x²+3x+1
a=2 b=3 c=1
D=(3)²-4(2)(1)
D=9-8=1
Since D is positive therefore it has real roots
Answered by
0
Answer:
Two-distinct roots
Step-by-step explanation:
To find the nature of roots we use the formula b^2-4ac
If,
b^2-4ac<0, there is no real roots,
b^2-4ac>0, there are two distinct roots,
b^2-4ac=0, there are equal roots(coincident roots)
Here,
a=2
b=3
c=1
Now,
b^2-4ac= 3^2-4*2*1
=9-8
=1
So here, root 1>0
So, this equation will have Two distinct roots..
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