Math, asked by sashankc28, 8 months ago

find the nature of the roots of 2x^2+3x+1=0

Answers

Answered by singlamonika1980
1

Step-by-step explanation:

Nature of roots is given by calculating the discriminant

D=b²-4ac

2x²+3x+1

a=2 b=3 c=1

D=(3)²-4(2)(1)

D=9-8=1

Since D is positive therefore it has real roots

Answered by BlaahhBlaahh
0

Answer:

Two-distinct roots

Step-by-step explanation:

To find the nature of roots we use the formula b^2-4ac

If,

b^2-4ac<0, there is no real roots,

b^2-4ac>0, there are two distinct roots,

b^2-4ac=0, there are equal roots(coincident roots)

Here,

a=2

b=3

c=1

Now,

b^2-4ac= 3^2-4*2*1

=9-8

=1

So here, root 1>0

So, this equation will have Two distinct roots..

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