Find the nature of the roots of 2x2 + 3x + 1 = 0.
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Answered by
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Hey buddy here is your answer
2x^2 + 3x + 1 = 0
here a = 2
b = 3
c = 1
Then discriminant = b^2 - 4ac
=>3^2 - 4(2)(1)
=>9 - 8
=>1
since D > 0
hence this equation has two distinct real roots
Hope it helps
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Answered by
0
Answer:
sorry I can't understand your question correctly
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