Find the nature of the roots of 3x'2 - 4√3x+4=0
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Answer:
3x
2
−4
3
x+4=0
a=3,b=−4
3
,c=4
Discriminant D=b
2
−4ac
=(−4
3
)
2
−4(3)(4)=48−48=0
⇒D=0
⇒ Two roots are equal.
The roots are
=
2a
−b±
D
=
2×3
4
3
±0
=
3
2
,
3
2
Hence, the roots are
3
2
and
3
2
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