Question

find the nature of the roots of 3x²-2√6x+2=0 if they exist find them ​

Answer 1

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3x² - 2√6 + 2 = 0

here,

• a = 3
• b = -2√6
• c = 2

now, determinant

d = b² - 4ac

➪ d = (-2√6)² - 4 × 3 × 2

➪ d = 24 - 24

➪ d = 0

since, determinant = 0

so, nature of roots is real and equal.

Answer 2

Answer:

3x² - 2√6 + 2 = 0

here,

a = 3

b = -2√6

c = 2

now, determinant

d = b² - 4ac

➪ d = (-2√6)² - 4 × 3 × 2

➪ d = 24 - 24

➪ d = 0

since, determinant = 0

so, nature of roots is real and equal.

Step-by-step explanation:

Hope it helps you.....