Question

find the nature of the roots of a quadratic equation 2x²-3x+5=0​

Answer 1

$\large\bf\underline{Question:}$

Find the nature of the roots of a quadratic equation 2x²-3x+5=0.

$\large\bf\underline{Solution:}$

Equation : 2x²-3x+5=0

a = 2

b = -3

c = 5

$\boxed{\sf{D=b^{2}-4ac}}$

D = (-3)² - 4(2)(5)

D = 9 - 40

D = -31

Since D < 0.

Hence, the equation has two imaginary(complex) roots.

Rules:

If D > 0, equation has two real and distinct roots.

If D < 0, equation has two complex roots.

If D = 0, equation has two real and equal roots.

____________________

Answer 2

Answer: Imaginary and different

Step-by-step explanation:

b^2 - 4ac < 0

9 - 40 < 0

-31 < 0