Question

find the nature of the roots of a quadratic equqtion 3x^2-4√3x+4
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Answer 1

Answer:

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$= 3 {x}^{2} - 4 \sqrt{3}x + 4$

Comparing with ax²+bx+c

we get ,

$a = 3 \: , \: b = - 4 \sqrt{3} \: , \: c = 4$

$d = {b}^{2} - 4ac$

$d = ( { - 4 \sqrt{3} )}^{2} - 4(3)(4)$

$d = 48 - 48$

$d = 0$

Nature of roots = two equal roots

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