find the nature of the roots of equation X square - 2 X + 3 is equal to zero
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2x2 – 7x + 3 = 0. On comparing this equation with ax2 + bx + c = 0, we get a = 2, b = -7 and c = 3. By using quadratic formula, we get x
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here
a=1, b=-2, c=3,
then
D=b²-4ac,
(-2)²-4×1×3,
4-12,
-8,
since D<0,
therefore
roots will be imaginary or not real
a=1, b=-2, c=3,
then
D=b²-4ac,
(-2)²-4×1×3,
4-12,
-8,
since D<0,
therefore
roots will be imaginary or not real
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