Math, asked by rohtashsharma63, 10 months ago

find the nature of the roots of following quardic equation 4x^2+2x-4=0​

Answers

Answered by saharounak093
1

Answer:

Step-by-step explanation:here a=4,b=2,c=-2

D=b^2-4ac=4-{4.4.(-4}=4+64=68

D>0

So the roots are real and unequal

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