Question

find the nature of the roots of quadratic equation 2x^2-√3x-2=0​

Answer 1

Answer:

comparing the given equation with

${ax}^{2} + bx + c = 0$

Here,

$a = 2 \: \\ b = \sqrt{3} \\ c \: = - 2$

${b}^{2} - 4ac \\ = { \sqrt{3} }^{2} - 4 \times 2 \times ( - 2) \\ =3 + 16 \\ =19$

Nature of root are real and unequal

Mark as brainliest pls