Question

Find the nature of the roots of quadratic equation 3x²-4√3x+4=0
Distinct real roots
Real and equal roots
No real roots​

Answer 1

Answer:

Real and equal roots

Step-by-step explanation:

We can find the nature of roots of a given qadratic equation can be found by determining the value of b²-4ac known as the disciminant.

On comparing the given qaudratic equation with ax²+bx+c=0, we have

a=3, b=-4√3 and c=4

D=b²-4ac

D= (-4√3)²-4(3)(4)

D=48-48

D=0

Since D=0, Therefore the given quadratic equation has Real and equal roots.

Remember:

1. If D<0, No real roots

2. If D>0, Real and Distinct Roots

3. If D=0, Real and Equal Roots