Question

find the nature of the roots of quadratic equation root 2 x square minus 3 by root 2 X + 1 by root 2 equals to zero

Answer 1

Hello Friend ✌
Here is u r Ans ➡

✨
$= \sqrt{2} x {}^{2} - \frac{3}{ \sqrt{2} } x + \frac{1}{ \sqrt{2} } = 0$

$2x {}^{2} - \frac{3x}{ \sqrt{2} } + \frac{ \sqrt{2} }{2} = 0$

$\sqrt{2} x {}^{2} - \frac{3 \sqrt{2}x }{2} + \frac{ \sqrt{2} }{2} = 0$

$2 \sqrt{2} x {}^{2} - 3 \sqrt{2} x + \sqrt{2} = 0$

$= 2x {}^{2} - 3x + 1 = 0$

$2x {}^{2} - x - 2x + 1 = 0$
$= x \times (2x - 1) - (2x - 1) = 0$
$(2x - 1)(x - 1) = 0$


$2x - 1 = 0 \\ x - 1 = 0$

$x = \frac{1}{2} and \: \\ x = 1$

⭐In decimal form ➡
$x = 0.5 \\ x = 1$
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Answer 2

Hope it helps........
:-)