Question

find the nature of the roots of quadratic equation Xsquere -6x+9=0​

Answer 1

Answer:

 

x² - 6x + 9 =0

⇒ x² - 3x-3x+9 = 0

⇒ x(x - 3) -3(x-3) = 0

⇒ (x - 3)×(x -  3) = 0

⇒ x = 3

∴ the  roots  of  the  equation  are  real.