find the nature of the roots of the equation x^2-16=0
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x²-16 = 0
Comparing the equation with ax²+bx +c =0
a=1, b=0 and c= -16
D= b²-4ac
D = (0)²-4(1)(-16)
D = 64
D > 0
So, the given equation has two distinct real roots.
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