Math, asked by muthu40301, 11 months ago

find the nature of the roots of the equation x^2-16=0​

Answers

Answered by ishwarsinghdhaliwal
1

x²-16 = 0

Comparing the equation with ax²+bx +c =0

a=1, b=0 and c= -16

D= b²-4ac

D = (0)²-4(1)(-16)

D = 64

D > 0

So, the given equation has two distinct real roots.

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