Question

Find the nature of the roots of the equation x^2+2x+(1/3)=0​

Answer 1

Answer:

*comparing equation x²+2x+(1/3)=0 with ax²+bx+c = 0

a = 1 , b = 2 , c = 1/3

b²- 4ac

= (2)² - 4×1×1/3

= 4 - 4×1/3

= 0 × 1/3

= 0

b²-4ac = 0

the roots are real and equal *

Answer 2

Answer:

Answer:

*comparing equation x²+2x+(1/3)=0 with ax²+bx+c = 0

a = 1 , b = 2 , c = 1/3

b²- 4ac

= (2)² - 4×1×1/3

= 4 - 4×1/3

= 0 × 1/3

= 0

b²-4ac = 0

the roots are real and equal *

Step-by-step explanation:

Hope this answer will help you.✌️