Question

Find the nature of the roots of the following quadratic equations. If real roots exist, find them:
i]6x^2-x-1=0

Answer 1

Answer:

Step-by-step explanation:

Here the eqn is 6x^2-x-1=0

From this eqn... a=6;b= -1;c= -1

The condition b^2-4ac is... 25

b^2-4ac > 0

Therefore the roots are real and distinct.

Now by factorisation...

6x^2-x-1=0

(3x-1)(2x-1)=0

x=1/3,1/2