find the nature of the roots of the following quadratic equations 2x^2-6x+3=0....plz tell me the answer
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Answer:
We could find the nature of roots by finding Discriminant
By using the Formula
b^2-4ac
(-6)^2-4×2×3
36-24
12>0
Therefore 12>0 then the given quadratic eq. have distinct real roots
Sorry but ur question was incomplete(2x^2-6x(+-)3??? I gave the +value
please mark as brainliast answer,.........................................
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