find the nature of the roots of the following quadratic equation x^2-7x+12=0
Answers
Answered by
2
Answer:
A. 3x
2
+7x+2=0
△=b
2
−4ac=7
2
−4(2)(3)=49−24=25>0
∴Roots are real and positive
B. (x+3)
2
+4x+7=0
x
2
+9+6x+4x+7=0
x
2
+10x+16=0
△=b
2
−4ac=100−4(16)=36=6
2
>0
∴Roots are real and positive
C. 2x
2
−8x+34=0
△=8
2
−4(2)(34)<0
∴ Roots are imaginary
D. x
2
+2
3
x−1=0
△=(2
3
)
2
+4(1)=12+4=16>0
Roots are real and positive.
Step-by-step explanation:
Answered by
2
Step-by-step explanation:
x^2-7x+12=0
let be
D = b^2-4ac
D = (-7)^2-4×2×12
= 49-96
= -47 -47<0 D<0
Roots are not real they are imagenry.
hope its helpful for you.....
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