Question

find the nature of the roots of the following quadratic equation 10 x² -7x +13 = 0.​

Answer 1

D = b² - 4 ac

= (-7)²-4.10.13

= 49 - 520

= - 471

since D < 0

roots are not real

Answer 2

Answer:

NO REAL ROOTS

Step-by-step explanation:

10x square - 7 x + 13 = 0

a = 10

b = -7

c = 13

d = b square - 4ac

d = (-7) - 4 * 10 * 13

d = 49 - 520

d = - 471

so it has no real roots