find the nature of the roots of the following
quadratic equation. If the real roots exust, find
them :
4x²-12x+9=0
Answers
Answered by
2
Answer:
Use the formula -b √b^2-2ac/2a
Step-by-step explanation:
Here a is 4 , b is -12 and C is 9
Hope it helps .
Answered by
6
Answer:
4x²-12x+9=0.
4x²-6x-6x+9 =0.
2x(2x-3) -3(2x-3)=0.
(2x -3)(2x-3)=0.
X = 3/2.
so roots of this equation is a real root.
Similar questions