Question

find the nature of the roots of the following
quadratic equation. If the real roots exust, find
them :
4x²-12x+9=0​

Answer 1

Answer:

Use the formula -b √b^2-2ac/2a

Step-by-step explanation:

Here a is 4 , b is -12 and C is 9

Hope it helps .

Answer 2

Answer:

4x²-12x+9=0.

4x²-6x-6x+9 =0.

2x(2x-3) -3(2x-3)=0.

(2x -3)(2x-3)=0.

X = 3/2.

so roots of this equation is a real root.