find the nature of the roots of the following quadratic equation :- 10x²-7x+13=0
Answers
Question
Find the nature of the roots of the following quadratic equation :-
10x²-7x+13=0
Answer
10x² - 7x + 13 = 0
Let
a = 10
b = -7
c = 13
Discriminant = b² - 4ac
= (-7)² - 4 × 10 × 13
= 49 - 520
= -471
Since the value is negative, therefore the nature of roots is imaginary or not real.
Must Know
b2-4ac = 0 → The roots are real, equal and rational
b2-4ac = 0 → The roots are real, equal and rational
b2 - 4ac > 0 but not a perfect square→The roots are real, distinct and irrational
b2-4ac<0 → The roots are imaginary
b2 - 4ac >/= 0 →The roots are real
Q) Find the nature of the roots of the following Quadratic Equation :- 10x² - 7x + 13 = 0 .
☆ Given :-
- The Quadratic Equation : 10x² - 7x + 13 = 0
☆ To Find :-
- The nature of the roots .
☆ Solution :-
We know that the standard Quadratic Equation is in the form -
After Comparing it with the given Equation ; we get :
- a = 10
- b = -7
- c = 13
To know the nature of the roots , we have to find it's Discriminant (d)
As you can see
Roots are Imaginary or Unreal / Not - Real .
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☆ Know More :-
• If ,
• If ,
• If ,
• The degree of the Quadratic Polynomial is 2 .
• A Quadratic Polynomial has 2 roots , they maybe distinct or real .
• The roots of a Quadratic Equation can be found by Middle term splitting or using Quadratic Formula .