Question

Find the nature of the roots of the following quadratic equation 2x^2+x+4=0

Answer 1

Answer:

2x^2+x+4=0

a=2 b=1 c=4

Step-by-step explanation:

discriminant= b^2-4ac

=1^2-4×2×4

=1-32

=-31

therefore,as b^2-4ac <0,

the given equation is not real and distinct.