Find the nature of the roots of the following quadratic equations,
(ii) x^2 -2 (√ 3)x - 1 = 0,
If real roots exist, find them,
hey plz any one answer
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Step-by-step explanation:
we have to check the discriminant value for the nature of the roots
b^2-4ac= [2(√3)]^2 - 4(1)(-1) = 4(3)+4=12+4=16
As D>0 so the quadratic eq. has distinct real roots.
by quadratic formula,
x= [-b±√(b^2-4ac)]/2a
x=(2√3±4)/2=√3±2
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