find the nature of the roots of the following quadratic equation. if the real roots exist,find them.
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for the nature of the roots we have to find the discriminant of the given equation
D = b²-4ac
= 48-48
D = 0
thus the roots are real and equal
it is the perfect square of √3x - 2
so (√3x-2)²=0
therefore the value of X is 2/√3
D = b²-4ac
= 48-48
D = 0
thus the roots are real and equal
it is the perfect square of √3x - 2
so (√3x-2)²=0
therefore the value of X is 2/√3
Answered by
6
This is the answer to the question
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kashisharora116:
I have done in same way but my teacher cross it
first you have to find discriminrnt and then the answer
In totaly this way I have solved
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