Find the nature of the roots of the following qudratic equation. if the real roots exist, find them: 2x^2-6x+3=0
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Step-by-step explanation:
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Hi mate ..
Here is your answer
Step-by-step explanation:
We could find the nature of roots by finding Discriminant
By using the Formula
b^2-4ac
(-6)^2-4×2×3
36-24
12>0
Therefore 12>0 then the given quadratic eq. have distinct real roots
Sorry but ur question was incomplete(2x^2-6x(+-)3??? I gave the +value
For more explanation..
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