Question

find the nature of the roots of the quadratic equation: 13√3x^2 + 10x + √3=0.

Answer 1

Answer:

Step-by-step explanation:

Answer 2

a = 13√3 , b = 10, c = 3  

b^2 – 4ac = (10)^2 – 4(13√3)(3)

= 100 – 156

= – 56  

As b^2 –4ac < 0

So, the equation has no real roots