Question

Find the nature of the roots of the quadratic equation:
13V3 x2 + 10x + V3 = 0​

Answer 1

Step-by-step explanation:

b^2-4ac

100-4*13*3

100-156

-56<0

i.e. D <0

Hence the roots are complex (imaginery)

Answer 2

Step-by-step explanation:

13√3×2x²+10x+√3=0

26√3+10x+√3=0

a=26√3 b=10 c=√3

b²-4ac= 10²-4×26√3×√3

= 100-4×26×3

=100-312

= -212

therefore, it's has no real roots and -212<0