Question

Find the nature of the roots of the quadratic equation 3xsquare-4√3x+4=0

Answer 1

Discriminent = b^2 - 4*a*c

D = (-4root3)^2 - 4(3)(4)

D = 48 - 48

D = 0

Discriminent = 0

So,

The roots are real and equal

Answer 2

(3x)×(3x)-4root3x+4=0
9 (x)×(x)-4+4root3x=0
9 (x)×(x)root3x=0