Find the nature of the roots of the quadratic equation √2x²-3x÷√2+1÷√2=0
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hey mate please refer to the attachment
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Dividing by root 2,we get,
2x2-3x+1=0
Here, a=2,b=-3 & c=1
Discreminant =b2-4ac
= 9-8
= 1
D > 0
Roots are real and distinct.
Step-by-step explanation:
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