find the nature of the roots of the quadratic equation
2x²-6x+3=0
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Answer:
We could find the nature of roots by finding Discriminant
By using the Formula
b^2-4ac
(-6)^2-4×2×3
36-24
12>0
Therefore 12>0 then the given quadratic eq. have distinct real roots
Sorry but ur question was incomplete(2x^2-6x(+-)3??? I gave the +value
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