find the nature of the roots of the quadratic equation 2x²-2√6x+3=0, if the real roots exist, then find them
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3x^{2}x
2
-2√6x+2=0
3x^{2}x
2
-√6x-√6x+2=0
√3x^{2}x
2
*√3x^{2}x
2
-√3x*√2x-√3x*√2x+√2*√2=0
√3x(√3x-√2)-√2(√3x-√2)=0
(√3x-√2)(√3x-√2)=0
x=√2/√3
Therefore the equation has two equal roots; √2/√3
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