Find the nature of the roots of the quadratic equation 2x2-6x 3=0.if the roots are real, find them.
Answers
Answered by
251
We could find the nature of roots by finding Discriminant
By using the Formula
b^2-4ac
(-6)^2-4×2×3
36-24
12>0
Therefore 12>0 then the given quadratic eq. have distinct real roots
Sorry but ur question was incomplete(2x^2-6x(+-)3??? I gave the +value
By using the Formula
b^2-4ac
(-6)^2-4×2×3
36-24
12>0
Therefore 12>0 then the given quadratic eq. have distinct real roots
Sorry but ur question was incomplete(2x^2-6x(+-)3??? I gave the +value
Answered by
521
HEYA!
Your Answer is in the attachment. Please refer to it.
The discriminant formula ( b^2 - 4ac ) is used .
CONDITIONS-
•If discriminant > zero , then it has real and unequal roots.
•If discriminant = zero , then it has real and equal roots.
•If discriminant < zero , then it has unreal roots.
Note- You forgot to give the sign of c i.e. 3 .So I supposed it to be +ve.
Hope this Helps!
Your Answer is in the attachment. Please refer to it.
The discriminant formula ( b^2 - 4ac ) is used .
CONDITIONS-
•If discriminant > zero , then it has real and unequal roots.
•If discriminant = zero , then it has real and equal roots.
•If discriminant < zero , then it has unreal roots.
Note- You forgot to give the sign of c i.e. 3 .So I supposed it to be +ve.
Hope this Helps!
Attachments:
Similar questions