Question

find the nature of the roots of the quadratic equation 2x2-x+1/8=0​

Answer 1

Step-by-step explanation:

${2 x}^{2} - x + \frac{1}{8} = 0 \\ \\ \frac{16 {x}^{2} - 8x + 1}{8} = 0 \\ \\ 16 {x}^{2} - 8x + 1 = 8 \times 0 \\ 16 {x}^{2} - 4x - 4x + 1 = 0 \\ 4x(4x - 1)1(4x - 1) = 0 \\ (4x + 1)(4x - 1)$

I hope it helps you

Answer 2

Answer:

HOPE THIS WILL HELP YOU

PLZ.. MARK THIS ANSWER AS BRAINLIEST