Question

Find the nature of the roots of the quadratic equation 2x2 - x -6=0​

Answer 1

Answer:

given quadratic equation 2x² - x -6 = 0

on comparing with standard form ax² + bx + c =0, we get

a = 2, b= -1 and c= -6

now, discriminant d = b² - 4ac

(-1)² - 4x2x(-6) => 1 + 48

D = 49 [ D > 0]

therefore, the nature of roots will be real and distinct