Find the nature of the roots of the quadratic equation 3x2 -2√6 x + 2 = 0
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Answered by
5
Explanation:
Here ,
a = 3
b = -2√6
c = 2
D = ( -2√6 ) ² - 4(3)(2)
D = 24 - 24
D = 0
It's seen that D = 0 and hence , the given equation has only 1 real and equal root .
Answered by
1
Answer:
Hence x =√⅔ and x= √⅔are roots of the equation
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