Question

Find the nature of the roots of the quadratic equation √3x² -3/√3x + 1/√3 = 0​

Answer 1

Answer:

a= √3, b= -3/√3 =-√3 , c= 1/√3

∆= b^2 - 4ac

= (-√3)^2 - 4(√3)(1/√3)

= 9 - 4×3

= 9 - 12

= -3

Roots are not real