find the nature of the roots of the quadratic equation
4x^2-5x+3=0
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Heyaa!
Here is your answer to the ques
Given: 4x²-5x+3=0
On comparing with ax²+bx+c=0 , we get
a=4 , b= -5 , c= 3
Now,
Discriminat = b²- 4ac
D. =(-5)² - (4×4×3)
= 25 - 48
= (-23)
As D>0 , so there will be no real roots.
Hope it will help you!
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