Question

Find the nature of the roots of the quadratic equation 4x2 + 4 √3x + 3 = 0​

Answer 1

Step-by-step explanation:

For nature=>

D = b^2 - 4ac

D = (4√3) ^2 - 4(4) (3)

= 16×3 - 48

= 0

so roots are real and equal