find the nature of the roots of the quadratic equation 4x²-5x+3=0
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Answers
Answered by
32
Heya !!!
The given equation is 4X² - 5X + 3 = 0
This equation is of the form of AX² + BX + C = 0
Where,
A = 4 , B = -5 and C = 3
Therefore,
Discriminant (D) = B² - 4AC
=> (-5)² - 4 × 4 × 3
=> ( 25) - (48)
=> -23 <0
-23 is smaller than 0 so the given equation has no real zeroes.
★ HOPE IT WILL HELP YOU ★
The given equation is 4X² - 5X + 3 = 0
This equation is of the form of AX² + BX + C = 0
Where,
A = 4 , B = -5 and C = 3
Therefore,
Discriminant (D) = B² - 4AC
=> (-5)² - 4 × 4 × 3
=> ( 25) - (48)
=> -23 <0
-23 is smaller than 0 so the given equation has no real zeroes.
★ HOPE IT WILL HELP YOU ★
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Answered by
46
Heya !!!
Here is your answer.
Given :
4x²-5x+3=0
On comparing with ax² + bx + c = 0, we get
a = 4, b = -5 and c = 3.
Discrimanant = b² - 4ac
= (-5)² - 4 × 4 × 3
= 25 - 48
= -23.
As D > 0, so there will be no real root.
It will be having two imaginary roots.
Hope You Got It
Here is your answer.
Given :
4x²-5x+3=0
On comparing with ax² + bx + c = 0, we get
a = 4, b = -5 and c = 3.
Discrimanant = b² - 4ac
= (-5)² - 4 × 4 × 3
= 25 - 48
= -23.
As D > 0, so there will be no real root.
It will be having two imaginary roots.
Hope You Got It
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