Find the nature of the roots of the quadratic equation
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Answer :
roots of given quadratic equation :
Ans = X = - 3√2 or X = √2
given quadratic equation
x^2 + 2√2x - 6 = 0
spilitting the middle term , we get
=> x^2+3√2x-√2x-6 = 0
=> x²+3√2x-√2x-√2×3√2 = 0
=> x(x+3√2)-√2(x+3√2)=0
=> (x+3√2)(x-√2)=0
=> x+3√2=0 Or x-√2=0
=> x = -3√2 Or x = √2
Therefore,
Roots of given quadratic equation :
x = -3√2 Or x = √2
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