Question

find the nature of the roots of the quadratic equation x^2-5x-7-0

Answer 1

Answer:

➡x²-5x-7 = 0

✏ a = 1 , b = -5 , c = -7

✍ b²-4ac = (-5)²-4.1.-7

=> 25+28

=> 53 > 0

Hence, the nature of the roots

is real and unequal.

Step-by-step explanation:

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Answer 2

Answer:-

${x}^{2} - 5x - 7 = 0 \\ \\ a = 1 \\ \\ b = - 5 \\ \\ c = - 7 \\ \\ D = {b}^{2} - 4ac \\ \\ \implies \: {( - 5)}^{2} - 4 \times (1) \times ( - 7) \\ \\ \implies \: 25 + 28 \\ \\ \implies \: 53 </u><u>></u><u>0</u><u>\\ \\ \bf \blue{hence \: the \: \: nature \: \: of \: \: the \: \: root \: \: is \: \: real \: \: and \: \: unequal}$