Question

Find the nature of the roots of the Quardiratic equation 3x×x-4√3x+4=0.if the real roots exist,find them​

Answer 1

Step-by-step explanation:

We have,

$3 {x}^{2} - 4 \sqrt{3} \: x + 4 = 0$

Here, a > 0

Now,

Discriminant, D =

${ (- 4 \sqrt{3} )}^{2} - 4 \times 4 \times 3 = 48 - 48 =0$

so, roots are real and equal