Question

find the nature of the roots off the quardratic equation 4x²-4x+1=0​

Answer 1

Answer:

Step-by-step explanation:

For nature of roots just find the discriminant of given quadratic

here a=4, b=-4 and c=1

now Discriminant

D= $b^2-4ac$

D=(-4)^2 -4(4)(1)

D=16-16=0

so here D=0 as per condition it has equal and real roots

NOTE conditions if D>0 then real and unequal roots

                            if D<0 then it has complex roots

                            if D=0 it has real and equal roots

Answer 2

both are equal root

Step-by-step explanation:

4x^2-4x+1=0

b^2-4ac=0

(-4)^2-4(4)(1)=0

16-16=0

0=0

If the b^2 - 4ac = 0 then both root are equal.