Question

Find the nature of the triangle whose vertices are A(12, 8), B(-2, 6) & C(6, 0).

Answer 1

Here is your answer friend

Answer 2

The nature of the triangle is right angle triangle.

Step-by-step explanation:

Given : Triangle whose vertices are A(12, 8), B(-2, 6) & C(6, 0).

To find : The nature of the triangle ?

Solution :

Vertices are A(12, 8), B(-2, 6) and C(6, 0)

The length of side AB is

$AB^2= (12-(-2))^2 + (8-6)^2\\\\AB^2= 196+4\\\\AB^2=200$

The length of side AC is

$AC^2= (12-6)^2 + (8-0)^2\\\\AC^2= 36+64\\\\AC^2=100$

The length of side BC is

$BC^2= (-2-6)^2 + (6-0)^2\\\\BC^2= 64+36\\\\BC^2=100$

Using Pythagoras theorem,

$AB^2 = AC^2+ BC^2\\\\200=100+100\\\\200=200$

The points (12, 8), (-2, 6) and (6, 0) are vertices of a right angled triangle.

Therefore, the nature of the triangle is right angle triangle.

#Learn more

If the vertices of the triangle are collinear. Find the area of that triangle​

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