Question

find the nature root of equation 3x²-4√3x+4​

Answer 1

We have,

3x² -4√3x+4

To find the nature of the roots of the above equation

Note:

Discriminant:

Discriminant is the value of b²-4ac

Implies,

When an equation is compared to ax²+bx+c=0,the solution of B²-4AC is known as Discriminant of that equation

When the Discriminant,D of a quadratic equation is:

•D=0,Real and equation roots

•D<0, Imaginary Roots

•D>0,Real and Distinct Roots

Now,

3x²-4√3x+4

Comparing with ax²+bx+c=0,

a=3,b= -4√3 and c=4

Here,

D=b²-4ac

=(-4√3)²-4(3)(4)

=48-48

=0

As D=0,the roots are equal and real

Answer 2

Step-by-step explanation:

Hi,

3x² - 4√3x + 4

Here,

Coefficient of x² = a = 3

Coefficient of x = b = -4√3

And,

Constant term = c = 4

Therefore,

Discriminant ( D ) = b² - 4ac

=> (-4√3)² - 4 × 3 × 4.

=> 48 - 48

=> 0

Discriminant = 0 , So the quadratic polynomial has real roots.

Hope it will help you :)