find the nature root of x2-6x+56
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Answer:
No real roots.
Step-by-step explanation:
x² - 6x + 56, a = 1, b = -6, c = 56
To find the nature of the roots, we must find the discriminant of the polynomial.
D = b² - 4ac
= (-6)²- 4 x 1 x 56
= 36 - 224
D = -188
Since D is less than 0,
The roots are not real.
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