Math, asked by omshrivastava68270, 1 month ago

find the nature roots of 5x²-2√15x+13=0

Answers

Answered by tennetiraj86
8

Step-by-step explanation:

Given:-

5x^2-2√15x+13=0

To find:-

Find the nature roots of 5x^2-2√15x+13=0 ?

Solution:-

Given quardratic equation is 5x^2-2√15x+13=0

On comparing this with the standard quadratic equation ax^2+bx+c = 0

a = 5

b = -2√15

c = 13

To find the nature of the roots of the above equation then we have to find the value of its discriminant.

We know that

ax^2+bx+c = 0 is a quardratic equation then the discriminant is D = b^2-4ac

=>D = (-2√15)^2-4(5)(13)

=> D = 60-260

=> D = -200 < 0

Since , D<0 the equation has no real roots .i.e. It has imaginary roots.

Answer:-

Nature of the roots :

No real roots.i.e. It has imaginary roots.

Used formulae:-

  • The standard quadratic equation is ax^2+bx+c = 0
  • ax^2+bx+c = 0 is a quardratic equation then the discriminant is D = b^2-4ac
  • Discriminant is used to know the nature of the roots .
  • If D>0 ,it has two distinct and real roots.
  • If D<0 ,it has no real roots.i.e.imaginary roots.
  • If D= 0 ,it has real and equal roots
Answered by harshit9927
3

5x^{2}-2\sqrt{15} x+13

Now, we have to find discriminant (D)

If,

D<0 then Complex roots

D>0 then Real and distrinct roots

D=0 then Real and equal roots

D=b^{2}-4ac

In the given equation :-

a = 5

b= -2\sqrt{15}

c = 13

D=(-2\sqrt{15}) ^{2}-4(5)(13)\\D=60-260\\D=-200

Hence, the nature of roots is complex

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