Question

Find the nature roots of quadratic equation2x+1/3x=5​

Answer 1

Step-by-step explanation:

2x+1/3x=5

6x²+1=15x

6x²-5×+1=0

By quadratic equation

x=-b+-root(b²-4ac)

___________

2a

a=6

b=-5

c=1

B5 putting the values of a b c in quadratic equation you get your answer

Answer 2

Answer:

it has two distinct real roots

Step-by-step explanation:

given,

          2x+1/3x=5

 take lcm

           6x^2+1=15x

           6x^2-15x+1=0

nature of roots=b^2-4ac

                        =(15)^2-4(6)(1)

                        =225-24

                        =201

therefore,

                b^2-4ac > 0

therefore,

                it has two distinct real roots

hope you understand

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