Question

Find the negative real root of the equation 81x 2 – 1 = 0.​

Answer 1

Answer:

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The answer is x = 1/9. and x = -1/9

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Step-by-step explanation:

$81 {x}^{2} - 1 = 0 \\ \\ 81 {x}^{2} = 1 \\ \\ {x}^{2} = \frac{1}{81} \\ \\taking \: square \: root \: on \: both \: sides \\ \\ \sqrt{ {x}^{2} } = \sqrt{ \frac{1}{81} } \\ \\ x = \frac{1}{9} \: \: \: \: \: and \: \: \: \: \: x = - \frac{1}{9} \\ \\ the \: negative \: real \: root \: of \: this \: equation \: is \: - \frac{1}{9} \\ \\ this \: is \: ur \: required \: answer \: :):):):):)$