Find the net deviation by mirrors as given in below image
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Answer:
Where is your image ?
but it's ok I have the answer
It is the angle made by the refleced ray with the direction of incident ray. Since OA' is just an extension to the incident ray path AO, ∠AOA' = 180°. Thus, δ = (180° - 2i). The angle of incidence 'i' can vary from 0° to 180° and correspondingly the deviation produced varies from 180° to 0°.It is the angle made by the refleced ray with the direction of incident ray. Since OA' is just an extension to the incident ray path AO, ∠AOA' = 180°. Thus, δ = (180° - 2i). The angle of incidence 'i' can vary from 0° to 180° and correspondingly the deviation produced varies from 180° to 0°.It is the angle made by the refleced ray with the direction of incident ray. Since OA' is just an extension to the incident ray path AO, ∠AOA' = 180°. Thus, δ = (180° - 2i). The angle of incidence 'i' can vary from 0° to 180° and correspondingly the deviation produced varies from 180° to 0°.
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